ITPEC IP April 2026 Question 80
ITPEC IP April 2026 — Question 80 of 100
8 points — Company A must exceed Company C's current leading weighted total.
Without brand, A scores 1×10 + 4×10 + 3×6 = 68. B scores 1×9 + 4×7 + 3×10 + 2×6 = 79; C scores 1×6 + 4×9 + 3×7 + 2×10 = 83. If A's brand score is x, its total is 68 + 2x. To lead, 68 + 2x > 83, so x > 7.5; the minimum integer is 8.
Answer (c)
Why not others: Scores (a) 6 and (b) 7 give totals 80 and 82; (d) 9 works but is not minimum.
Key rule: Multiply each rating by its weight, compare totals, and use a strict inequality when “best” means sole highest score.
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