ITPEC IP October 2022 Question 53
ITPEC IP October 2022 — Question 53 of 100
The number of communication paths increases by a factor of three. For n people, every pair forms one path, giving n(n−1)/2. Six members require 6×5/2 = 15 paths; ten require 10×9/2 = 45. The factor is 45/15 = 3.
Answer (c)
Why not others:
- the path count grows quadratically rather than in direct proportion to headcount
- 1.5, 2.5, and 6 do not match the calculated ratio
Key rule: A fully connected team's communication channels equal the number of unordered member pairs.
AI-generated — may contain errors
The original exam layout is preserved in the image so diagrams, formulas, tables, and code remain accurate.
This question comes from an official ITPEC past paper. ITPEC Practice is an independent study tool and is not affiliated with ITPEC. See the official IP past-paper collection or Report an issue.