ITPEC IP April 2025 Question 54
ITPEC IP April 2025 — Question 54 of 100
3 times — the number of one-to-one communication paths is n(n - 1) ÷ 2.
With six members, there are 6 × 5 ÷ 2 = 15 distinct pairs. With ten members, there are 10 × 9 ÷ 2 = 45 pairs. The increase factor is 45 ÷ 15 = 3.
Answer (c)
Why not others:
- (a) 1.5 is the ratio of added paths to the new total, 30 ÷ 20, not the required factor
- (b) 2.5 does not result from the pair-count formula
- (d) 6 overstates the growth by treating communication paths as more than distinct member pairs
Key rule: A fully connected team has one channel per unordered pair, so channels grow quadratically rather than in direct proportion to headcount.
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