ITPEC FE Morning October 2021 Question 54

The activities and nodes of a project are shown in the arrow diagram below. Which of the following is the effect of extending the duration of activity C by 3 days?

A3B4D6C5F7E6G5H1
Legend:NodeActivityActivity nameNumber of days requiredDummy activity

Explanation

Extended by 2 days — lengthening C makes its path 2 days longer than the current critical path.

Every path from start to end, before the change (C = 5):

PathDays
A → D → E → H3 + 6 + 6 + 1 = 16
A → D → dummy → G → H3 + 6 + 0 + 5 + 1 = 15
B → C → E → H4 + 5 + 6 + 1 = 16
B → C → dummy → G → H4 + 5 + 0 + 5 + 1 = 15
B → F → G → H4 + 7 + 5 + 1 = 17

The critical path is B → F → G → H, 17 days. The longest path through C is 16 days, so C has a total float of 1 day. With C = 8, B → C → E → H becomes 4 + 8 + 6 + 1 = 19 days, the new critical path: the project grows from 17 to 19 days.

Answer (c)

Why not others:

  • •(a) — true only if C's float were at least 3 days; it is 1 day.
  • •(b) — follows only the path through the dummy, B → C → dummy → G → H, which becomes 18 days, and misses the longer path through E.
  • •(d) — treats C as critical; its 1 day of float absorbs one of the three days.

Key rule: Delaying an activity lengthens the project by the delay minus the activity's total float, when that is positive; find the float from the longest path through the activity.

Project Management · AI-written, may contain errors

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