ITPEC FE Morning October 2021 Question 54
The activities and nodes of a project are shown in the arrow diagram below. Which of the following is the effect of extending the duration of activity C by 3 days?
Explanation
Extended by 2 days — lengthening C makes its path 2 days longer than the current critical path.
Every path from start to end, before the change (C = 5):
The critical path is B → F → G → H, 17 days. The longest path through C is 16 days, so C has a total float of 1 day. With C = 8, B → C → E → H becomes 4 + 8 + 6 + 1 = 19 days, the new critical path: the project grows from 17 to 19 days.
Answer (c)
Why not others:
- •(a) — true only if C's float were at least 3 days; it is 1 day.
- •(b) — follows only the path through the dummy, B → C → dummy → G → H, which becomes 18 days, and misses the longer path through E.
- •(d) — treats C as critical; its 1 day of float absorbs one of the three days.
Key rule: Delaying an activity lengthens the project by the delay minus the activity's total float, when that is positive; find the float from the longest path through the activity.
Project Management · AI-written, may contain errors
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