ITPEC FE Morning April 2020 Question 53
Source exam: ITPEC FE Morning April 2020Topic: Project Management
ITPEC FE Morning April 2020 — Question 53 of 80
The critical path is the longest path through the network, determining the minimum project duration.
Calculate each path's total duration:
- •(a) A→B→E→I→L:
2+3+1+2+3= 11 days - •(b) A→C→D→E→H→K:
2+3+1+1+3+2= 12 days - •(c) A→C→F→I→L:
2+3+3+2+3= 13 days - •(d) A→C→G→J→L:
2+3+4+2+3= 14 days ✅
Why not others:
- (a) 11 days — shortest path, plenty of slack
- (b) 12 days — not the longest
- (c) 13 days — close but 1 day shorter than (d)
Key rule: The critical path is the longest path from start to finish — any delay on it delays the entire project.
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