ITPEC IP April 2026 Question 7

Source exam: ITPEC IP April 2026Topic: Algorithm and Programming

ITPEC IP April 2026 — Question 7 of 100

State 4 — calculate the remainder again after the first transition, using the newly reached state.

Start at state 1.

  • First execution: 1 × 11 = 11, and 11 mod 3 = 2. Remainder 2 means move two states clockwise: 1 → 2 → 3.
  • Second execution uses state 3: 3 × 11 = 33, and 33 mod 3 = 0. Remainder 0 means move one state clockwise: 3 → 4.

The final state is 4.

Answer (d)

Why not others:
- (a) incorrectly returns to the starting state

- (b) represents only the first of the two clockwise steps required by the first remainder

- (c) is the intermediate state after the procedure has run once, not twice

Key rule: In repeated state transitions, each iteration uses the state produced by the previous iteration; recompute the condition rather than repeating the first move.

AI-generated — may contain errors

The original exam layout is preserved in the image so diagrams, formulas, tables, and code remain accurate.

This question comes from an official ITPEC past paper. ITPEC Practice is an independent study tool and is not affiliated with ITPEC. See the official IP past-paper collection or Report an issue.