ITPEC IP October 2022 Question 8
ITPEC IP October 2022 — Question 8 of 100
After two executions, the state is 4. Starting at state 1, 1 × 11 leaves remainder 2 when divided by 3, so move two states clockwise: 1 to 2 to 3. Next, 3 × 11 = 33 leaves remainder 0, so move one state clockwise from 3 to 4.
Answer (d)
Why not others:
- states 1, 2, and 3 do not follow both specified remainder-based transitions
Key rule: Recalculate the remainder from the newly reached state before performing the second transition.
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