ITPEC FE Subject A October 2024 Question 12

Source exam: ITPEC FE Subject A October 2024Topic: Computer Systems & Hardware

ITPEC FE Subject A October 2024 — Question 12 of 60

System Availability (series-parallel) — calculate combined availability of a mixed topology.

Given devices: A(0.8), B(0.7), C(0.9), D(0.7), E(0.8)

Step 1 — Parallel groups:
- A ∥ B = 1 - (1-0.8)(1-0.7) = 1 - 0.06 = 0.94

- D ∥ E = 1 - (1-0.7)(1-0.8) = 1 - 0.06 = 0.94

Step 2 — Series connection:
- Total = 0.94 × 0.9 × 0.94 = 0.795

Why not others:
- (a) 0.003 — multiplied all five availabilities in series

- (b) 0.031 — incorrect formula application

- (c) 0.282 — likely swapped parallel/series formulas

Key rules:
- Parallel: 1 - (1-A)(1-B) — system works if either device works

- Series: A × B — system works only if both devices work

AI-generated — may contain errors

The original exam layout is preserved in the image so diagrams, formulas, tables, and code remain accurate.

This question comes from an official ITPEC past paper. ITPEC Practice is an independent study tool and is not affiliated with ITPEC. See the official FE past-paper collection or Report an issue.