ITPEC FE Morning April 2022 Question 34
Source exam: ITPEC FE Morning April 2022Topic: Networks
ITPEC FE Morning April 2022 — Question 34 of 80
Broadcast Address Calculation — find the broadcast address from CIDR notation.
Given 192.168.128.0/26:
- •Prefix length =
26→ host bits =32 - 26=6 - •Block size =
2^6=64 - •Broadcast =
0 + 64 - 1=63 - •Result =
192.168.128.63
Why not others:
- (b) 192.168.128.127 — broadcast for /25 (block size 128)
- (c) 192.168.128.252 — not a valid broadcast for any standard subnet
- (d) 192.168.128.255 — broadcast for /24 (block size 256)
Key rule: Broadcast = network address + 2^(32 − prefix) − 1. All host bits set to 1.
AI-generated — may contain errors
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