ITPEC FE Morning April 2020 Question 63
ITPEC FE Morning April 2020 — Question 63 of 80
Weighted Comprehensive Evaluation — multiply each score by its weight and sum to find the best option.
Calculate the weighted total for each proposal:
- •Proposal 1:
4×6 + 3×5 + 3×6 = 24 + 15 + 18 = 57 - •Proposal 2:
4×8 + 3×5 + 3×4 = 32 + 15 + 12 = 59 - •Proposal 3:
4×2 + 3×9 + 3×7 = 8 + 27 + 21 = 56 - •Proposal 4:
4×5 + 3×5 + 3×6 = 20 + 15 + 18 = 53
Proposal 2 has the highest weighted score (59), so it should be prioritized.
Why not others:
- (a) Proposal 1 scores 57 — second highest but still less than 59
- (c) Proposal 3 scores 56 — strong in time and resources but weak in labor savings (weight 4), which drags it down
- (d) Proposal 4 scores 53 — lowest overall
Key rule: In weighted evaluation, multiply each criterion's score by its weight, then sum — the highest total wins. Criteria with higher weights have more influence on the result.
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