ITPEC FE Morning April 2020 Question 19
ITPEC FE Morning April 2020 — Question 19 of 80
Virtual Memory Paging — calculate the number of pages from address space and page size.
Given a 32-bit virtual address space mapped to 4 KB pages:
- •Total address space:
2^32bytes - •Page size:
4 KB=4 × 1024=2^12bytes - •Number of pages:
2^32 ÷ 2^12= 2^20
Why not others:
- (a) 2^4 — only 16 pages; far too few for a 32-bit space
- (b) 2^10 — would require a page size of 2^22 (4 MB), not 4 KB
- (d) 2^32 — total number of addressable bytes, not pages
Key rule: Number of pages = 2^(address bits) ÷ page size. With powers of two, subtract exponents: 32 - 12 = 20.
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