ITPEC FE Morning October 2020 Question 15

Which of the following achieves data redundancy via mirroring?

Explanation

RAID 1 — mirroring writes the same data to two disks, so either disk alone holds a full copy.

  • •RAID 0: striping only, data spread across disks for speed, no redundancy
  • •RAID 1: mirroring, an identical copy on a second disk
  • •RAID 5: striping with one parity block per stripe, distributed across disks; survives one disk failure
  • •RAID 6: striping with two parity blocks per stripe; survives two disk failures

Answer (b)

Why not others:

  • •(a) RAID 0 — stripes data with no redundancy at all; losing one disk loses the array
  • •(c) RAID 5 — gets redundancy from parity, rebuilding lost data by calculation, not from a mirror copy
  • •(d) RAID 6 — the same idea as RAID 5 with double parity, again not mirroring

Key rule: RAID redundancy comes either from copies (RAID 1, mirroring, 50% usable capacity) or from parity (RAID 5 and 6, one or two disks' worth of capacity lost).

System Component · AI-written, may contain errors

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