ITPEC IP April 2025 Question 9
ITPEC IP April 2025 — Question 9 of 100
1 — trace both boxes using quotient remainders.
For the left box, A1 = 49 and A2 = 11, so B1 = 11 and B2 = 49 mod 11 = 5. These two outputs become the right box's inputs: A1 = 11 and A2 = 5. The right box therefore produces B2 = 11 mod 5 = 1.
Answer (a)
Why not others:
- (d) 5 is the remainder from only the first box
- (b) 2 is the quotient of 11 ÷ 5, but B2 is defined as the remainder
- (c) 4 is the quotient of 49 ÷ 11, again confusing quotient with remainder
Key rule: In a connected data-flow diagram, calculate each block completely, then use its actual outputs as the next block's inputs.
AI-generated — may contain errors
The original exam layout is preserved in the image so diagrams, formulas, tables, and code remain accurate.
This question comes from an official ITPEC past paper. ITPEC Practice is an independent study tool and is not affiliated with ITPEC. See the official IP past-paper collection or Report an issue.