ITPEC IP April 2020 Question 67
ITPEC IP April 2020 — Question 67 of 100
Preparing 100 lunch boxes requires 6,000 grams of meat. Each box contains five dumplings, so 100 boxes need 500 dumplings. At 20 grams of stuffing each, that requires 10,000 grams of stuffing. Meat is 60 grams per 100 grams of stuffing, so meat required is 10,000×0.60 = 6,000 grams.
Answer (c)
Why not others:
- the other quantities omit either the dumplings-per-box factor, the stuffing-per-dumpling factor, or the 60% meat ratio
Key rule: Expand the bill of materials level by level and multiply quantities through every parent-child relationship.
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