ITPEC FE Subject B April 2025 Question 5
ITPEC FE Subject B April 2025 — Question 5 of 20
Expressing math formulas with pow() — translate (√x + √y)² into nested pow() calls.
The formula breaks down as:
- √x = pow(x, 0.5) (square root is the same as raising to 0.5)
- √y = pow(y, 0.5)
- (...)² = pow(..., 2)
Combined: pow(pow(x, 0.5) + pow(y, 0.5), 2)
Verification with calc(4, 9): pow(pow(4,0.5) + pow(9,0.5), 2) = pow(2 + 3, 2) = pow(5, 2) = 25 ✓
Why not others:
- (b) Squares each root separately then adds: pow(2,2) + pow(3,2) = 4 + 9 = 13 ≠ 25
- (c) Takes the square root of the sum of squares: pow(16 + 81, 0.5) ≈ 9.85 ≠ 25
- (d) Returns √x + √y without squaring: 2 + 3 = 5 ≠ 25
- (e) Divides √x + √y by √2: (2 + 3) / 1.414 ≈ 3.54 ≠ 25
- (f) Divides x² + y² by √2: (16 + 81) / 1.414 ≈ 68.6 ≠ 25
Key rule: pow(a, 0.5) = √a and pow(a, 2) = a². Nest them to match the original formula structure.
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