ITPEC FE Morning October 2022 Question 11

Bus Data Transfer Rate — calculate max throughput from clock, bus width, and cycle ratio.

Given: 32-bit bus, 64 MHz clock, 8 clocks per bus cycle.

• •Bus width = 32 bits = 4 bytes per transfer
• •Bus cycle frequency = 64,000,000 / 8 = 8,000,000 cycles/sec
• •Transfer rate = 8,000,000 × 4 = 32,000,000 bytes/sec = 32 MB/s

Answer: (b) 32

Why not others:
- (a) 3 — arithmetic error or wrong unit conversion
- (c) 256 — ignores the 8-clock-per-bus-cycle divisor (64 × 4 = 256)
- (d) 320 — incorrect calculation path

Key formula: transfer_rate = (clock_freq ÷ clocks_per_bus_cycle) × (bus_width ÷ 8)

AI-generated — may contain errors