ITPEC FE Morning April 2022 Question 31
ITPEC FE Morning April 2022 — Question 31 of 80
Audio buffering time — calculate minimum buffer before playback starts.
Given:
- Audio size: 2.4 MB = 19.2 Mbit
- Encoding rate: 192 kbit/s
- Network speed: 128 kbit/s
Solution:
- Playback duration: 19.2 Mbit ÷ 192 kbit/s = 100 s
- Full download time: 19.2 Mbit ÷ 128 kbit/s = 150 s
- Download continues during playback, so: 128 × (T + 100) ≥ 19,200
- T + 100 ≥ 150 → T ≥ 50
- Minimum buffering time = 50 seconds
Why not others:
- (b) 100 — playback duration, not buffering time
- (c) 150 — total download time if no parallel playback
- (d) 250 — does not match any calculation
Key rule: Buffering time = total_download_time − playback_duration. Download continues during playback (streaming model).
AI-generated — may contain errors
The original exam layout is preserved in the image so diagrams, formulas, tables, and code remain accurate.
This question comes from an official ITPEC past paper. ITPEC Practice is an independent study tool and is not affiliated with ITPEC. See the official FE past-paper collection or Report an issue.