ITPEC FE Morning April 2021 Question 30
Which of the following is the response time when a client and server at different locations communicate under the conditions below? Here, the response time is in seconds and starts from the moment the client sends a message until a response is received from the server. 1 MB is 106 bytes. The propagation delay between the client and server can be ignored.
[Conditions]
Explanation
5.8 seconds — two transfers at the effective line speed plus the processing time on both sides.
- •Effective speed: 8 × 0.6 = 4.8 Mbit/s, and 4.8 ÷ 8 = 0.6 MB/s
- •Upstream: 1 ÷ 0.6 ≈ 1.67 s; downstream: 2 ÷ 0.6 ≈ 3.33 s; together 3 ÷ 0.6 = 5.0 s
- •Processing: 0.4 + 0.4 = 0.8 s
- •Response time: 5.0 + 0.8 = 5.8 s
Answer (d)
Why not others:
- •(a) 1.4 — reads the line speed as 8 MB/s instead of 8 Mbit/s: 3 ÷ 4.8 ≈ 0.6 s, plus 0.8 s
- •(b) 3.8 — ignores the 60% efficiency: 3 MB is 24 Mbit, 24 ÷ 8 = 3.0 s, plus 0.8 s
- •(c) 5.0 — the transmission time alone, leaving out the 0.8 s of client and server processing
Key rule: Apply the efficiency and convert bits to bytes before dividing, then add every step the message passes through in sequence: both transfers and the processing at each end.
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