ITPEC FE Morning April 2020 Question 32
ITPEC FE Morning April 2020 — Question 32 of 80
Satellite Communication Delay — calculate total propagation delay through a geostationary satellite.
Signal path: A → satellite → B (two legs + relay delay).
- •Distance per leg:
37,500 km - •Speed of radio waves:
3 × 10⁸ m/s = 3 × 10⁵ km/s - •Relay delay at satellite:
10 ms = 0.01 s
Calculation:
- •One leg:
37,500 / 300,000 = 0.125 s - •Two legs:
0.125 × 2 = 0.25 s - •Total:
0.25 + 0.01 = 0.26 s
Answer: b) 0.26
Why not others:
- (a) 0.13 — only one leg (A → satellite), forgot the second leg
- (c) 0.35 — wrong distance or extra delays added
- (d) 0.52 — possibly doubled the relay delay or miscalculated
Key rule: Use the given distance (37,500 km), not the altitude (36,000 km). The satellite is not directly overhead, so actual signal path > altitude.
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