ITPEC FE Morning October 2018 Question 26
ITPEC FE Morning October 2018 — Question 26 of 80
Audio Sampling & Storage Calculation — compute maximum recording time from memory size.
Given: 11,000 samples/sec, 8 bits/sample, 512 × 10⁶ bytes flash memory.
Step-by-step:
- Data rate: 11,000 × 8 bits = 88,000 bits/sec = 11,000 bytes/sec
- Time in seconds: 512 × 10⁶ / 11,000 ≈ 46,545 sec
- Time in minutes: 46,545 / 60 ≈ 775.75 → 775 minutes
Why not others:
- (a) 77 — off by a factor of 10
- (b) 96 — likely mixed up bit/byte conversion
- (d) 969 — forgot to convert 8 bits to 1 byte (divided by 8,800 instead of 11,000)
Key rule: recording_time = memory_size / (sampling_rate × bits_per_sample / 8). Always convert bits to bytes first.
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