IPA IP 2025 Question 99

Topic: Algorithm and Programming

A question IPA Japan published in 令和7年度 ITパスポート試験 公開問題 問99, translated into English. ITPEC is based on the same exams.

The function calculateAmountOfPrize receives the improvement amount and the reduction period in the effects of a business improvement as improvement and period respectively, and returns the prize amount as the return value. There were a business improvement with an improvement amount of 200,000 yen and a reduction period of 3 days, and a business improvement with an improvement amount of 50,000 yen and a reduction period of 14 days. How many yen is the total of these two prize amounts? Here, the values of the improvement amount and the reduction period are each 0 or more.

[Program]
○ integer: calculateAmountOfPrize(integer: improvement, // Improvement amount (yen)
integer: period) // Reduction period (days)
integer: prize // Prize amount (yen)
if (improvement is less than 100000)
if (period is less than 7)
prize ← 500
else
prize ← 1000
endif
else
if (period is less than 7)
prize ← 2000
else
prize ← 5000
endif
endif
return prize

Explanation

3,000 yen — trace each improvement through the two nested if statements and add the prizes.

The outer if splits on the improvement amount (below 100,000 yen or not), the inner one on the reduction period (below 7 days or not):

  • •200,000 yen, 3 days: improvement is not less than 100000, so the else branch; period 3 is less than 7, so prize ← 2000
  • •50,000 yen, 14 days: improvement is less than 100000; period 14 is not less than 7, so prize ← 1000

Total: 2,000 + 1,000 = 3,000 yen. Running the function on both inputs gives the same.

Answer (c)

Why not others:

  • •(a) 1,000 — counts only the second improvement's prize
  • •(b) 1,500 — gives the 200,000-yen improvement 500, as if it were below 100,000 yen
  • •(d) 5,500 — gives the 200,000-yen improvement 5000 and the other 500, swapping the two period tests

Key rule: With nested conditions, settle the outer test first, then the inner one inside that branch only, and check each boundary (“less than” excludes the value itself).

Algorithm and Programming · AI-written, may contain errors

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This question comes from the past questions IPA Japan publishes, translated into English by ITPEC Practice. ITPEC Practice is an independent study tool and is not affiliated with IPA or ITPEC. See the original paper (PDF) or Report an issue.